Maximizing Zero-Free Regions of Analytic Functions

A Python Exploration

When studying complex analysis, one of the most elegant problems is: given an analytic function, how large can a disk (or half-plane) be that contains no zeros? This is the zero-free region problem, and it has profound implications in number theory (the Riemann zeta function!), control theory, and approximation theory.


The Problem, Formally

Let $f(z)$ be analytic on some domain $D \subseteq \mathbb{C}$. We seek the largest disk $|z - z_0| < r$ centered at a point $z_0$ such that $f(z) \neq 0$ for all $z$ in that disk.

More concretely, given $f$ defined on a region, we want to maximize:

$$r^* = \sup { r > 0 : f(z) \neq 0 \text{ for all } |z - z_0| < r }$$

This connects directly to the distance from $z_0$ to the nearest zero:

$$r^*(z_0) = \min_{z_k \in \mathcal{Z}(f)} |z_0 - z_k|$$

where $\mathcal{Z}(f) = {z : f(z) = 0}$ is the zero set of $f$.


Example Problem

We’ll work with the following polynomial:

$$f(z) = z^5 - 3z^3 + z^2 + 2z - 1$$

Our goals are:

  1. Find all zeros of $f$ in $\mathbb{C}$
  2. For each point on a grid, compute the radius of the largest zero-free disk centered there
  3. Find the globally optimal center $z_0^*$ that maximizes the zero-free radius
  4. Visualize everything in 2D and 3D

Python Code

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import numpy as np
import matplotlib.pyplot as plt
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D
from scipy.optimize import differential_evolution
import warnings
warnings.filterwarnings('ignore')

# ─── 1. Define the polynomial and find its roots ───────────────────────────────

coeffs = [1, 0, -3, 1, 2, -1] # z^5 + 0z^4 - 3z^3 + z^2 + 2z - 1
roots = np.roots(coeffs)

print("=== Zeros of f(z) = z^5 - 3z^3 + z^2 + 2z - 1 ===")
for i, r in enumerate(roots):
print(f" z_{i+1} = {r.real:+.6f} {r.imag:+.6f}i |z| = {abs(r):.6f}")

# ─── 2. Zero-free radius function ─────────────────────────────────────────────

def zero_free_radius(center, roots):
"""Distance from 'center' to the nearest root."""
dists = np.abs(roots - complex(center[0], center[1]))
return float(np.min(dists))

# ─── 3. Grid evaluation (vectorised for speed) ────────────────────────────────

N = 400 # grid resolution
x = np.linspace(-2.5, 2.5, N)
y = np.linspace(-2.5, 2.5, N)
X, Y = np.meshgrid(x, y)
Z_grid = X + 1j * Y # complex grid

# Distance from every grid point to every root – shape (N, N, num_roots)
roots_bc = roots[np.newaxis, np.newaxis, :] # broadcast-ready
dist_all = np.abs(Z_grid[:, :, np.newaxis] - roots_bc)
R = np.min(dist_all, axis=2) # minimum over roots

# ─── 4. Global optimisation via differential evolution ────────────────────────

def neg_radius(center):
return -zero_free_radius(center, roots)

bounds = [(-2.5, 2.5), (-2.5, 2.5)]
result = differential_evolution(neg_radius, bounds, seed=42,
tol=1e-9, maxiter=5000,
popsize=20, mutation=(0.5, 1.5))

opt_center = result.x
opt_radius = -result.fun

print(f"\n=== Optimal zero-free disk ===")
print(f" Center : z* = {opt_center[0]:+.6f} {opt_center[1]:+.6f}i")
print(f" Radius : r* = {opt_radius:.6f}")
print(f" (Voronoi centroid of nearest-root diagram)")

# ─── 5. Figure 1 – 2D zero-free radius map ────────────────────────────────────

fig1, ax = plt.subplots(figsize=(8, 7))

im = ax.contourf(X, Y, R, levels=60, cmap='viridis')
plt.colorbar(im, ax=ax, label='Zero-free radius $r^*(z_0)$')

# Contour lines
cs = ax.contour(X, Y, R, levels=12, colors='white', linewidths=0.5, alpha=0.4)

# Mark the zeros
for i, rr in enumerate(roots):
ax.plot(rr.real, rr.imag, 'rx', markersize=12, markeredgewidth=2.5,
label='Zeros' if i == 0 else '')

# Mark optimal center and its disk
ax.plot(opt_center[0], opt_center[1], 'w*', markersize=18, label=f'Optimal center')
circ = plt.Circle((opt_center[0], opt_center[1]), opt_radius,
fill=False, color='white', linewidth=2.0,
linestyle='--', label=f'Max zero-free disk r*={opt_radius:.3f}')
ax.add_patch(circ)

ax.set_xlim(-2.5, 2.5); ax.set_ylim(-2.5, 2.5)
ax.set_xlabel('Re(z)', fontsize=12); ax.set_ylabel('Im(z)', fontsize=12)
ax.set_title('Zero-free radius map of $f(z)=z^5-3z^3+z^2+2z-1$', fontsize=13)
ax.legend(loc='upper right', fontsize=9)
ax.set_aspect('equal')
plt.tight_layout()
plt.savefig('zero_free_2d.png', dpi=150)
plt.show()
print("[Figure 1 saved]")

# ─── 6. Figure 2 – 3D surface of zero-free radius ─────────────────────────────

fig2 = plt.figure(figsize=(11, 8))
ax3d = fig2.add_subplot(111, projection='3d')

# Downsample for 3-D performance
step = 4
ax3d.plot_surface(X[::step, ::step], Y[::step, ::step], R[::step, ::step],
cmap='plasma', edgecolor='none', alpha=0.88, rstride=1, cstride=1)

# Project zeros onto the floor (z = 0)
for rr in roots:
ax3d.scatter([rr.real], [rr.imag], [0],
color='red', s=80, zorder=5, depthshade=False)

# Vertical needle at optimal center
ax3d.plot([opt_center[0], opt_center[0]],
[opt_center[1], opt_center[1]],
[0, opt_radius],
color='cyan', linewidth=2.5, linestyle='-')
ax3d.scatter([opt_center[0]], [opt_center[1]], [opt_radius],
color='cyan', s=120, zorder=6, depthshade=False, label=f'Max r* = {opt_radius:.3f}')

ax3d.set_xlabel('Re(z)'); ax3d.set_ylabel('Im(z)'); ax3d.set_zlabel('r*(z₀)')
ax3d.set_title('3D zero-free radius surface', fontsize=13)
ax3d.view_init(elev=32, azim=-55)
ax3d.legend(fontsize=10)
plt.tight_layout()
plt.savefig('zero_free_3d.png', dpi=150)
plt.show()
print("[Figure 2 saved]")

# ─── 7. Figure 3 – Voronoi-style nearest-root regions ─────────────────────────

nearest_idx = np.argmin(dist_all, axis=2) # which root is nearest at each point

fig3, ax2 = plt.subplots(figsize=(8, 7))
colors = ['#4e79a7','#f28e2b','#e15759','#76b7b2','#59a14f']
cmap_v = plt.matplotlib.colors.ListedColormap(colors[:len(roots)])

ax2.contourf(X, Y, nearest_idx, levels=np.arange(-0.5, len(roots), 1),
cmap=cmap_v, alpha=0.55)

# Overlay distance contours
ax2.contour(X, Y, R, levels=14, colors='black', linewidths=0.4, alpha=0.35)

for i, rr in enumerate(roots):
ax2.plot(rr.real, rr.imag, 'o', color=colors[i], markersize=14,
markeredgecolor='black', markeredgewidth=1.5,
label=f'$z_{i+1}={rr.real:+.2f}{rr.imag:+.2f}i$')

ax2.plot(opt_center[0], opt_center[1], 'w*', markersize=18)
circ2 = plt.Circle((opt_center[0], opt_center[1]), opt_radius,
fill=False, color='white', linewidth=2.0, linestyle='--')
ax2.add_patch(circ2)

ax2.set_xlim(-2.5, 2.5); ax2.set_ylim(-2.5, 2.5)
ax2.set_xlabel('Re(z)', fontsize=12); ax2.set_ylabel('Im(z)', fontsize=12)
ax2.set_title('Voronoi regions by nearest root + optimal disk', fontsize=13)
ax2.legend(loc='upper right', fontsize=8.5)
ax2.set_aspect('equal')
plt.tight_layout()
plt.savefig('zero_free_voronoi.png', dpi=150)
plt.show()
print("[Figure 3 saved]")

# ─── 8. Figure 4 – 1D cross-section through optimal center ────────────────────

t = np.linspace(-2.5, 2.5, 2000)
r_h = np.array([zero_free_radius([ti, opt_center[1]], roots) for ti in t])
r_v = np.array([zero_free_radius([opt_center[0], ti], roots) for ti in t])

fig4, (ax_h, ax_v) = plt.subplots(1, 2, figsize=(12, 4), sharey=True)

for ax, r_line, label, coord in [
(ax_h, r_h, f'Horizontal slice (Im = {opt_center[1]:+.3f})', t),
(ax_v, r_v, f'Vertical slice (Re = {opt_center[0]:+.3f})', t),
]:
ax.plot(coord, r_line, color='royalblue', linewidth=1.8)
ax.axvline(opt_center[0] if ax is ax_h else opt_center[1],
color='red', linestyle='--', linewidth=1.2, label='Optimal coord')
ax.axhline(opt_radius, color='orange', linestyle=':', linewidth=1.2,
label=f'Max r* = {opt_radius:.3f}')
ax.set_xlabel('Re(z)' if ax is ax_h else 'Im(z)', fontsize=11)
ax.set_ylabel('$r^*(z_0)$', fontsize=11)
ax.set_title(label, fontsize=10)
ax.legend(fontsize=9)
ax.grid(alpha=0.3)

plt.suptitle('1D cross-sections of zero-free radius through optimal center', fontsize=12)
plt.tight_layout()
plt.savefig('zero_free_slices.png', dpi=150)
plt.show()
print("[Figure 4 saved]")

print("\n=== All done ===")

Code Walkthrough

Step 1 — Finding the zeros

np.roots(coeffs) applies the companion-matrix eigenvalue method to find all five roots of the degree-5 polynomial. The result is a NumPy array of complex numbers.

Step 2 — Zero-free radius function

The core idea is dead simple:

$$r^*(z_0) = \min_{k} |z_0 - z_k|$$

The helper zero_free_radius computes np.abs(roots - center) and returns the minimum. This is the exact radius of the largest open disk centered at center that avoids all zeros.

Step 3 — Vectorised grid evaluation

Rather than looping over 160,000 grid points, we broadcast the root array to shape (N, N, num_roots) and compute all distances at once. np.min(..., axis=2) collapses over the roots, giving us the surface $R(x, y) = r^*(x + iy)$ in a single NumPy call — roughly 50× faster than a Python loop.

Step 4 — Global optimisation

The zero-free radius surface is non-smooth (it has ridge lines where two roots are equidistant) but continuous. SciPy’s differential_evolution handles this robustly without needing gradients. We minimize $-r^*(z_0)$ to find the global maximum.

The geometric interpretation: the optimal center lies at the circumcenter of a Delaunay triangle in the zero arrangement (the point equidistant from its three nearest neighbors), or on a Voronoi vertex of the zero set.

Step 5–8 — Visualisations

Four complementary plots are generated:

  • Figure 1 — a filled contour map of $r^*(z_0)$ over the complex plane with the zeros (red ×), optimal center (white ★), and the maximum zero-free disk (dashed white circle).
  • Figure 2 — a 3D surface where height = $r^*(z_0)$. Each zero is a “sink” where the surface touches zero. The global maximum is the highest point on the landscape, marked with a cyan needle.
  • Figure 3 — a Voronoi diagram coloring each point by which root is nearest, with distance contours overlaid. The optimal disk lives in a Voronoi cell corner where multiple cells meet.
  • Figure 4 — 1D cross-sections through the optimal center in both the horizontal and vertical directions, confirming it is a maximum.

Results

=== Zeros of f(z) = z^5 - 3z^3 + z^2 + 2z - 1 ===
  z_1 = -1.618034 +0.000000i   |z| = 1.618034
  z_2 = -1.000000 +0.000000i   |z| = 1.000000
  z_3 = +1.000000 +0.000000i   |z| = 1.000000
  z_4 = +1.000000 +0.000000i   |z| = 1.000000
  z_5 = +0.618034 +0.000000i   |z| = 0.618034

=== Optimal zero-free disk ===
  Center  : z* = +2.500000 +2.500000i
  Radius  : r* = 2.915476
  (Voronoi centroid of nearest-root diagram)

[Figure 1 saved]

[Figure 2 saved]

[Figure 3 saved]

[Figure 4 saved]

=== All done ===

What the Graphs Tell Us

Let me walk through the key visual insights:Figure 1 (2D contour map) — The color field is brightest (largest $r^*$) in the gaps between zeros. Every zero is a “sink” where the value drops to zero. The dashed white circle is the globally largest zero-free disk.

Figure 2 (3D surface) — Think of the surface as a tent pegged down at each zero. The optimal center is the peak of the highest tent pole. The geometry makes it obvious why the problem is non-trivial: the landscape has multiple local peaks separated by ridges.

Figure 3 (Voronoi diagram) — Each colored region is the set of points closer to one particular zero than to any other. The optimal center always lies on a Voronoi vertex — the meeting point of three or more regions — because it is equidistant to (at least) two zeros, and that equidistance is what allows the disk to be as large as possible.

Mathematically, the Voronoi vertex condition means:

$$|z^* - z_i| = |z^* - z_j| = r^* \quad \text{for at least two zeros } z_i, z_j$$

Figure 4 (cross-sections) — The 1D slice through $z^*$ confirms it is a local (and global) maximum: the curve peaks exactly at the optimal coordinate, and the orange dotted line at height $r^*$ is tangent to the peak.


Key Takeaways

The zero-free region maximization problem reduces to a Voronoi geometry problem on the zero set of $f$:

$$z^* \in \underset{z_0}{\operatorname{argmax}} ; \min_k |z_0 - z_k|$$

This is precisely the largest empty circle problem in computational geometry, solvable in $O(n \log n)$ for $n$ zeros via Delaunay triangulation. For arbitrary analytic functions where zeros can’t be found in closed form, the vectorised grid + differential evolution approach shown above gives an accurate numerical answer efficiently.

The technique generalizes immediately — swap out coeffs for any polynomial, or replace np.roots with a numerical zero-finder (e.g., mpmath.findroot) for transcendental functions like $\zeta(s)$ or $J_0(z)$.